-0.5x^2+1.25x+1.75=0

Solution for -0.5x^2+1.25x+1.75=0 equation:

-0.5x^2+1.25x+1.75=0

a = -0.5; b = 1.25; c = +1.75;
Δ = b2-4ac
Δ = 1.252-4·(-0.5)·1.75
Δ = 5.0625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1.25)-\sqrt{5.0625}}{2*-0.5}=\frac{-1.25-\sqrt{5.0625}}{-1}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1.25)+\sqrt{5.0625}}{2*-0.5}=\frac{-1.25+\sqrt{5.0625}}{-1}
$